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#!/bin/sh
# Ensure that sort --sort-random doesn't sort.

if test "$VERBOSE" = yes; then
  set -x
  sort --version
fi

pwd=`pwd`
t0=`echo "$0"|sed 's,.*/,,'`.tmp; tmp=$t0/$$
trap 'status=$?; cd $pwd; chmod -R u+rwx $t0; rm -rf $t0 && exit $status' 0
trap '(exit $?); exit $?' 1 2 13 15

framework_failure=0
mkdir -p $tmp || framework_failure=1
cd $tmp || framework_failure=1
seq 100 > in || framework_failure=1

if test $framework_failure = 1; then
  echo "$0: failure in testing framework" 1>&2
  (exit 1); exit 1
fi

fail=0

sort --random-sort in > out || fail=1

# Fail if the input is the same as the output.
# This is a probabilistic test :-)
# However, the odds of failure are very low: 1 in 100! (~ 1 in 10^158)
cmp in out > /dev/null && { fail=1; echo "not random?" 1>&2; }

# Fail if the sorted output is not the same as the input.
sort -n out > out1
cmp in out1 || { fail=1; echo "not a permutation" 1>&2; }

(exit $fail); exit $fail