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#!/bin/sh
# cp -RL dir1 dir2' must handle the case in which each of dir1 and dir2
# contain a symlink pointing to some third directory.
# Copyright (C) 2006 Free Software Foundation, Inc.
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2 of the License, or
# (at your option) any later version.
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA
# 02110-1301, USA.
if test "$VERBOSE" = yes; then
set -x
cp --version
fi
pwd=`pwd`
t0=`echo "$0"|sed 's,.*/,,'`.tmp; tmp=$t0/$$
trap 'status=$?; cd "$pwd" && chmod -R u+rwx $t0 && rm -rf $t0 && exit $status' 0
trap '(exit $?); exit $?' 1 2 13 15
framework_failure=0
mkdir -p $tmp || framework_failure=1
cd $tmp || framework_failure=1
mkdir a b c d || framework_failure=1
ln -s ../c a || framework_failure=1
ln -s ../c b || framework_failure=1
if test $framework_failure = 1; then
echo "$0: failure in testing framework" 1>&2
(exit 1); exit 1
fi
fail=0
# Before coreutils-5.94, the following would fail with this message:
# cp: will not create hard link `d/b/c' to directory `d/a/c'
cp -RL a b d || fail=1
test -d a/c || fail=1
test -d b/c || fail=1
(exit $fail); exit $fail
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