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#!/bin/sh
# make sure chgrp handles --recursive w/symlinks
if test "$VERBOSE" = yes; then
set -x
chgrp --version
fi
pwd=`pwd`
tmp=slink.$$
trap 'status=$?; cd $pwd; rm -rf $tmp && exit $status' 0
trap '(exit $?); exit' 1 2 13 15
framework_failure=0
mkdir $tmp || framework_failure=1
cd $tmp || framework_failure=1
if test $framework_failure = 1; then
echo 'failure in testing framework' 1>&2
(exit 1); exit
fi
groups=`id -nG 2>/dev/null`
case "$groups" in
*' '*) ;;
*) cat <<EOF 1>&2
$0: this test requires that you be a member of more than one group,
but running \`id -nG' either failed or found just one.
EOF
(exit 77); exit
;;
esac
set _ $groups; shift
g1=$1
g2=$2
fail=0
# chgrp -R should not traverse a symlink to a directory.
mkdir d e
touch e/f
ln -s ../e d/s
chgrp -R $g1 e/f || fail=1
# Neither of the following should change the group of e/f
chgrp -R $g2 d
set _ `ls -l e/f`; g=$5; test "$g" = $g1 || fail=1
chgrp --deref -R $g2 d
set _ `ls -l e/f`; g=$5; test "$g" = $g1 || fail=1
# Even when the symlink-to-directory is a command line argument, it should
# not be traversed. So this shouldn't change the group of e/f either.
chgrp --deref -R $g2 d/s || fail=1
set _ `ls -l e/f`; g=$5; test "$g" = $g1 || fail=1
(exit $fail); exit
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