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#!/bin/sh
# make sure chgrp is reasonable

if test "$VERBOSE" = yes; then
  set -x
  chgrp --version
fi

. $srcdir/../envvar-check
. $srcdir/../lang-default
. $srcdir/../group-names

pwd=`pwd`
tmp=basic.$$
trap 'status=$?; cd $pwd; rm -rf $tmp && exit $status' 0
trap '(exit $?); exit' 1 2 13 15

framework_failure=0
mkdir $tmp || framework_failure=1
cd $tmp || framework_failure=1

if test $framework_failure = 1; then
  echo 'failure in testing framework' 1>&2
  (exit 1); exit
fi

fail=0

set _ $groups; shift
g1=$1
g2=$2
mkdir d
touch f f2 d/f3
chgrp $g1 f || fail=1
chgrp $g2 f || fail=1
chgrp $g2 f2 || fail=1
chgrp -R $g1 d || fail=1

# Don't let verbose output interfere.
test "$VERBOSE" = yes && set +x

(
  chgrp -c $g1 f
  chgrp -c $g2 f
  chgrp -c $g2 f
  chgrp --verbose $g1 f
  chgrp --verbose $g1 f
  chgrp --verbose --reference=f2 f
  chgrp -R --verbose $g2 d
  chgrp -R --verbose $g1 d
  chgrp -R -c $g2 d
  chgrp -R -c $g1 d
  chgrp -c $g2 d

  rm -f f
  touch f
  ln -s f symlink
  chgrp $g1 f
  chgrp -h $g2 symlink 2> /dev/null

  # This should not change the group of f.
  chgrp -h -c $g2 symlink 2> /dev/null
  chgrp -c $g2 f

  # This *should* change the group of f.
  # Though note that the diagnostic is misleading in that
  # it says the `group of `symlink'' has been changed.
  chgrp --dereference -c $g1 symlink

) 2>&1 | sed "s/ $g1$/ G1/;s/ $g2$/ G2/" > actual

cat <<\EOF > expected
changed group of `f' to G1
changed group of `f' to G2
changed group of `f' to G1
group of `f' retained as G1
changed group of `f' to G2
changed group of `d' to G2
changed group of `d/f3' to G2
changed group of `d' to G1
changed group of `d/f3' to G1
changed group of `d' to G2
changed group of `d/f3' to G2
changed group of `d' to G1
changed group of `d/f3' to G1
changed group of `d' to G2
changed group of `f' to G2
changed group of `symlink' to G1
EOF

cmp expected actual \
  || { diff expected actual 1>&2; fail=1; }

(exit $fail); exit