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#!/bin/sh
# mdate-sh - get modification time of a file and pretty-print it
# Copyright (C) 1995 Software Foundation, Inc.
# Written by Ulrich Drepper <drepper@gnu.ai.mit.edu>, June 1995
#
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2, or (at your option)
# any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
# Prevent date giving response in another language.
LANG=C
export LANG
LC_ALL=C
export LC_ALL
LC_TIME=C
export LC_TIME
# Get the extended ls output of the file.
if ls -L /dev/null 1>/dev/null 2>&1; then
set - `ls -L -l $1`
else
set - `ls -l $1`
fi
# The month is at least the fourth argument.
# (3 shifts here, the next inside the loop)
shift
shift
shift
# Find the month. Next argument is day, followed by the year or time.
month=
until test $month
do
shift
case $1 in
Jan) month=January; nummonth=1;;
Feb) month=February; nummonth=2;;
Mar) month=March; nummonth=3;;
Apr) month=April; nummonth=4;;
May) month=May; nummonth=5;;
Jun) month=June; nummonth=6;;
Jul) month=July; nummonth=7;;
Aug) month=August; nummonth=8;;
Sep) month=September; nummonth=9;;
Oct) month=October; nummonth=10;;
Nov) month=November; nummonth=11;;
Dec) month=December; nummonth=12;;
esac
done
day=$2
# Here we have to deal with the problem that the ls output gives either
# the time of day or the year.
case $3 in
*:*) set `date`; eval year=\$$#
case $2 in
Jan) nummonthtod=1;;
Feb) nummonthtod=2;;
Mar) nummonthtod=3;;
Apr) nummonthtod=4;;
May) nummonthtod=5;;
Jun) nummonthtod=6;;
Jul) nummonthtod=7;;
Aug) nummonthtod=8;;
Sep) nummonthtod=9;;
Oct) nummonthtod=10;;
Nov) nummonthtod=11;;
Dec) nummonthtod=12;;
esac
# For the first six month of the year the time notation can also
# be used for file modified in the last year.
if (expr $nummonth \> $nummonthtod) > /dev/null;
then
year=`expr $year - 1`
fi
;;
*) year=$3;;
esac
# The result.
echo $day $month $year
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