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authorrubidium <rubidium@openttd.org>2007-04-18 22:41:53 +0000
committerrubidium <rubidium@openttd.org>2007-04-18 22:41:53 +0000
commit2ce514284cc358dc1216274ac20d37472bcc0550 (patch)
tree4c61df1a2939966a82e001dc46309bc70348feb2 /src/strings.cpp
parent7577954ced47f09803bc1b3881d47f222dbd306b (diff)
downloadopenttd-2ce514284cc358dc1216274ac20d37472bcc0550.tar.xz
(svn r9673) -Cleanup: remove spaces before tabs and replace non-indenting tabs with spaces.
Diffstat (limited to 'src/strings.cpp')
-rw-r--r--src/strings.cpp10
1 files changed, 5 insertions, 5 deletions
diff --git a/src/strings.cpp b/src/strings.cpp
index 45bf80de4..b0b6fb1a7 100644
--- a/src/strings.cpp
+++ b/src/strings.cpp
@@ -421,7 +421,7 @@ static int DeterminePluralForm(int32 n)
* Used in:
* Latvian */
case 3:
- return n%10 == 1 && n%100 != 11 ? 0 : n != 0 ? 1 : 2;
+ return n % 10 == 1 && n % 100 != 11 ? 0 : n != 0 ? 1 : 2;
/* Three forms, special case for one and two
* Used in:
@@ -433,25 +433,25 @@ static int DeterminePluralForm(int32 n)
* Used in:
* Lithuanian */
case 5:
- return n%10 == 1 && n%100 != 11 ? 0 : n%10 >= 2 && (n%100<10 || n%100 >= 20) ? 1 : 2;
+ return n % 10 == 1 && n % 100 != 11 ? 0 : n % 10 >= 2 && (n % 100 < 10 || n % 100 >= 20) ? 1 : 2;
/* Three forms, special cases for numbers ending in 1 and 2, 3, 4, except those ending in 1[1-4]
* Used in:
* Croatian, Czech, Russian, Slovak, Ukrainian */
case 6:
- return n%10 == 1 && n%100 != 11 ? 0 : n%10 >= 2 && n%10 <= 4 && (n%100<10 || n%100 >= 20) ? 1 : 2;
+ return n % 10 == 1 && n % 100 != 11 ? 0 : n % 10 >= 2 && n % 10 <= 4 && (n % 100 < 10 || n % 100 >= 20) ? 1 : 2;
/* Three forms, special case for one and some numbers ending in 2, 3, or 4
* Used in:
* Polish */
case 7:
- return n == 1 ? 0 : n%10 >= 2 && n%10 <= 4 && (n%100<10 || n%100 >= 20) ? 1 : 2;
+ return n == 1 ? 0 : n % 10 >= 2 && n % 10 <= 4 && (n % 100 < 10 || n % 100 >= 20) ? 1 : 2;
/* Four forms, special case for one and all numbers ending in 02, 03, or 04
* Used in:
* Slovenian */
case 8:
- return n%100 == 1 ? 0 : n%100 == 2 ? 1 : n%100 == 3 || n%100 == 4 ? 2 : 3;
+ return n % 100 == 1 ? 0 : n % 100 == 2 ? 1 : n % 100 == 3 || n % 100 == 4 ? 2 : 3;
}
}