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| author | frosch <frosch@openttd.org> | 2015-06-28 15:54:12 +0000 |
|---|---|---|
| committer | frosch <frosch@openttd.org> | 2015-06-28 15:54:12 +0000 |
| commit | 2e2b35c73362a036731f1a862bee00f571331635 (patch) | |
| tree | 13988f328ab46439cee0ad2c38244cbcfda42612 /src/gfx.cpp | |
| parent | a65a194416421750110b87da97787b57eb66fe98 (diff) | |
| download | openttd-2e2b35c73362a036731f1a862bee00f571331635.tar.xz | |
(svn r27323) -Fix: Spelling.
Diffstat (limited to 'src/gfx.cpp')
| -rw-r--r-- | src/gfx.cpp | 4 |
1 files changed, 2 insertions, 2 deletions
diff --git a/src/gfx.cpp b/src/gfx.cpp index aa55b29a2..79d46e23e 100644 --- a/src/gfx.cpp +++ b/src/gfx.cpp @@ -209,8 +209,8 @@ static inline void GfxDoDrawLine(void *video, int x, int y, int x2, int y2, int /* Imagine that the line is infinitely long and it intersects with * infinitely long left and right edges of the clipping rectangle. - * If booth intersection points are outside the clipping rectangle - * and booth on the same side of it, we don't need to draw anything. */ + * If both intersection points are outside the clipping rectangle + * and both on the same side of it, we don't need to draw anything. */ int left_isec_y = y + (clip.left - x) * grade_y / grade_x; int right_isec_y = y + (clip.right - x) * grade_y / grade_x; if ((left_isec_y > clip.bottom + margin && right_isec_y > clip.bottom + margin) || |