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#!/bin/sh
# see if chgrp can change the group of a symlink
if test "$VERBOSE" = yes; then
set -x
chgrp --version
fi
pwd=`pwd`
tmp=slink.$$
trap 'status=$?; cd $pwd; rm -rf $tmp && exit $status' 0
trap '(exit $?); exit' 1 2 13 15
framework_failure=0
mkdir $tmp || framework_failure=1
cd $tmp || framework_failure=1
if test $framework_failure = 1; then
echo 'failure in testing framework' 1>&2
(exit 1); exit
fi
groups=`id -nG 2>/dev/null`
case "$groups" in
*' '*) ;;
*) cat <<EOF 1>&2
$0: this test requires that you be a member of more than one group,
but running \`id -nG' either failed or found just one.
EOF
(exit 77); exit
;;
esac
set _ $groups; shift
g1=$1
g2=$2
touch f
ln -s f symlink
chgrp $g2 symlink 2> /dev/null
set _ `ls -l symlink`
g=$5
test "$g" = $g2 || {
cat <<EOF 1>&2
$0: skipping this test; your system doesn't support changing
the owner or group of a symbolic link.
EOF
(exit 77); exit
}
fail=0
chgrp $g1 f
set _ `ls -l f`; g=$5; test "$g" = $g1 || fail=1
chgrp $g2 symlink || fail=1
set _ `ls -l f`; g=$5; test "$g" = $g1 || fail=1
set _ `ls -l symlink`; g=$5; test "$g" = $g2 || fail=1
# This should not change the group of f.
chgrp $g2 symlink || fail=1
set _ `ls -l f`; g=$5; test "$g" = $g1 || fail=1
set _ `ls -l symlink`; g=$5; test "$g" = $g2 || fail=1
chgrp $g2 f
set _ `ls -l f`; g=$5; test "$g" = $g2 || fail=1
# This *should* change the group of f.
# Though note that the diagnostic you'd get with -c is misleading in that
# it says the `group of `symlink'' has been changed.
chgrp --dereference $g1 symlink
set _ `ls -l f`; g=$5; test "$g" = $g1 || fail=1
set _ `ls -l symlink`; g=$5; test "$g" = $g2 || fail=1
(exit $fail); exit
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