From 1d5b09348ebb3a8fad259a78d247b621ed1ae295 Mon Sep 17 00:00:00 2001
From: Jim Meyering <jim@meyering.net>
Date: Mon, 4 Dec 1995 16:29:54 +0000
Subject: .

---
 doc/mdate-sh | 92 ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 92 insertions(+)
 create mode 100755 doc/mdate-sh

diff --git a/doc/mdate-sh b/doc/mdate-sh
new file mode 100755
index 000000000..d01e00c25
--- /dev/null
+++ b/doc/mdate-sh
@@ -0,0 +1,92 @@
+#!/bin/sh
+# mdate-sh - get modifaction time of a file and pretty-print it
+# Copyright (C) 1995 Software Foundation, Inc.
+# written by Ulrich Drepper <drepper@gnu.ai.mit.edu>, June 1995
+#
+# This program is free software; you can redistribute it and/or modify
+# it under the terms of the GNU General Public License as published by
+# the Free Software Foundation; either version 2, or (at your option)
+# any later version.
+# 
+# This program is distributed in the hope that it will be useful,
+# but WITHOUT ANY WARRANTY; without even the implied warranty of
+# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
+# GNU General Public License for more details.
+# 
+# You should have received a copy of the GNU General Public License
+# along with this program; if not, write to the Free Software
+# Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
+
+# Prevent date giving response in another language
+LANG=C
+export LANG
+LC_ALL=C
+export LC_ALL
+LC_TIME=C
+export LC_TIME
+
+# Get the extended ls output of the file
+if ls -L /dev/null 1>/dev/null 2>&1; then
+  set - `ls -L -l $1`
+else
+  set - `ls -l $1`
+fi
+# The month is at least the fourth argument
+# (3 shifts here, the next inside the loop)
+shift
+shift
+shift
+
+# Find the month.  Next argument is day, followed by the year or time
+month=
+until test $month
+do
+  shift
+  case $1 in
+    Jan) month=January; nummonth=1;;
+    Feb) month=February; nummonth=2;;
+    Mar) month=March; nummonth=3;;
+    Apr) month=April; nummonth=4;;
+    May) month=May; nummonth=5;;
+    Jun) month=June; nummonth=6;;
+    Jul) month=July; nummonth=7;;
+    Aug) month=August; nummonth=8;;
+    Sep) month=September; nummonth=9;;
+    Oct) month=October; nummonth=10;;
+    Nov) month=November; nummonth=11;;
+    Dec) month=December; nummonth=12;;
+  esac
+done
+
+day=$2
+
+# Here we have to deal with the problem that the ls output gives either
+# the time of day or the year.
+case $3 in
+  *:*) set `date`; year=$7
+       case $2 in
+	 Jan) nummonthtod=1;;
+	 Feb) nummonthtod=2;;
+	 Mar) nummonthtod=3;;
+	 Apr) nummonthtod=4;;
+	 May) nummonthtod=5;;
+	 Jun) nummonthtod=6;;
+	 Jul) nummonthtod=7;;
+	 Aug) nummonthtod=8;;
+	 Sep) nummonthtod=9;;
+	 Oct) nummonthtod=10;;
+	 Nov) nummonthtod=11;;
+	 Dec) nummonthtod=12;;
+       esac
+       # For the first six month of the year the time notation can also
+       # be used for file modified in the last year.
+       if (expr $nummonth \> $nummonthtod) > /dev/null;
+       then
+	 year=`expr year - 1`
+       fi
+       ;;
+  *) year=$3;;
+esac
+
+# The result.
+echo $day $month $year
-- 
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